The solubility product for salt AB_2 is 4 tim | vedclass

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(C) The dissociation of the salt $AB_2$ is given by: $AB_2(s) \rightleftharpoons A^{2+}(aq) + 2B^{-}(aq)$.Let the solubility be $S \ mol \ L^{-1}$. Th

Vedclass · Accepted Answer

$1 	imes 10^{-4} \ mol \ L^{-1}$

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(C) The dissociation of the salt $AB_2$ is given by: $AB_2(s) ightleftharpoons A^{2+}(aq) + 2B^{-}(aq)$.Let the solubility be $S \ mol \ L^{-1}$. Then $[A^{2+}] = S$ and $[B^{-}] = 2S$.The solubility product expression is $K_{sp} = [A^{2+}][B^{-}]^2$.Substituting the values: $K_{sp} = (S)(2S)^2 = 4S^3$.Given $K_{sp} = 4 	imes 10^{-12}$,we have $4S^3 = 4 	imes 10^{-12}$.$S^3 = 10^{-12}$,which gives $S = (10^{-12})^{1/3} = 10^{-4} \ mol \ L^{-1}$.

The solubility product for salt $AB_2$ is $4 \times 10^{-12}$. Calculate its solubility.

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