Solubility product of $CaC_2O_4$ at a given temperature in pure water is $4 \times 10^{-9} \ (mol \ L^{-1})^2$. Solubility of $CaC_2O_4$ at the same temperature is
- A$6.3 \times 10^{-5} \ mol \ L^{-1}$
- B$2 \times 10^{-5} \ mol \ L^{-1}$
- C$2 \times 10^{-4} \ mol \ L^{-1}$
- D$6.3 \times 10^{-4} \ mol \ L^{-1}$
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