$A$ solution of $12 \ g$ of non-electrolyte $(A)$ prepared by dissolving it in $1000 \ mL$ of water exerts the same osmotic pressure as that of a $0.05 \ M$ glucose solution at the same temperature. The empirical formula of $A$ is $CH_2O$. The molecular mass of $A$ is $.......... \ g \ mol^{-1}$. (Nearest integer)
- A$241$
- B$242$
- C$240$
- D$243$
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$A$ $40 \text{ g}$ non-electrolyte solute having a molar mass of $180 \text{ g mol}^{-1}$ is dissolved in water to form a solution. If the osmotic pressure of the solution is $2 \text{ atm}$ at $300 \text{ K}$, calculate the volume of the solution in $\text{dm}^3$. $(R = 0.0821 \text{ L atm K}^{-1} \text{mol}^{-1})$ (in $\text{ dm}^3$)
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View SolutionWhat mass of solute (molar mass $58 \ g \ mol^{-1}$) is to be dissolved in $2.5 \ dm^3$ $H_2O$ to generate osmotic pressure of $0.245 \ atm$ at $300 \ K$ (in $g$)? $(R = 0.0821 \ dm^3 \ atm \ K^{-1} \ mol^{-1})$.
The molar mass of a solute $X$ in $g \ mol^{-1}$, if its $1 \%$ solution is isotonic with a $5 \%$ solution of cane sugar (molar mass $= 342 \ g \ mol^{-1}$), is
Osmotic pressure is $0.0821 \ atm$ at a temperature of $300 \ K$. Find the concentration in $mol/L$.
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View SolutionIf the osmotic pressure of a solution at $300 \ K$ is $0.0821 \ atm$,what will be the concentration of the solution in $mol/L$?
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