Solve the equation for x, y, z and t if2begin | vedclass

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(A) Given the equation:$2\begin{bmatrix} x & z \ y & t \end{bmatrix} + 3\begin{bmatrix} 1 & -1 \ 0 & 2 \end{bmatrix} = 3\begin{bmatrix} 3 & 5 \ 4 &

Vedclass · Accepted Answer

$x=3, y=6, z=9, t=6$

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(A) Given the equation:$2\begin{bmatrix} x & z \ y & t \end{bmatrix} + 3\begin{bmatrix} 1 & -1 \ 0 & 2 \end{bmatrix} = 3\begin{bmatrix} 3 & 5 \ 4 & 6 \end{bmatrix}$Multiplying the matrices by the scalars:$\begin{bmatrix} 2x & 2z \ 2y & 2t \end{bmatrix} + \begin{bmatrix} 3 & -3 \ 0 & 6 \end{bmatrix} = \begin{bmatrix} 9 & 15 \ 12 & 18 \end{bmatrix}$Adding the matrices on the left side:$\begin{bmatrix} 2x+3 & 2z-3 \ 2y+0 & 2t+6 \end{bmatrix} = \begin{bmatrix} 9 & 15 \ 12 & 18 \end{bmatrix}$Comparing the corresponding elements:$1) 2x+3 = 9 \Rightarrow 2x = 6 \Rightarrow x = 3$$2) 2z-3 = 15 \Rightarrow 2z = 18 \Rightarrow z = 9$$3) 2y = 12 \Rightarrow y = 6$$4) 2t+6 = 18 \Rightarrow 2t = 12 \Rightarrow t = 6$Thus,$x=3, y=6, z=9, t=6$.

Solve the equation for $x, y, z$ and $t$ if
$2\begin{bmatrix} x & z \\ y & t \end{bmatrix} + 3\begin{bmatrix} 1 & -1 \\ 0 & 2 \end{bmatrix} = 3\begin{bmatrix} 3 & 5 \\ 4 & 6 \end{bmatrix}$

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Solve the equation for $x, y, z$ and $t$ if$2\begin{bmatrix} x & z \\ y & t \end{bmatrix} + 3\begin{bmatrix} 1 & -1 \\ 0 & 2 \end{bmatrix} = 3\begin{bmatrix} 3 & 5 \\ 4 & 6 \end{bmatrix}$