Solve the following equation using the method | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given equation: $x^{2}+3x-5=0$.To complete the square,we add and subtract the square of half the coefficient of $x$,which is $(\frac{3}{2})^{2} =

Vedclass · Accepted Answer

$\frac{-3-\sqrt{29}}{2}$ and $\frac{-3+\sqrt{29}}{2}$

Vedclass · Answer

(C) Given equation: $x^{2}+3x-5=0$.To complete the square,we add and subtract the square of half the coefficient of $x$,which is $(\frac{3}{2})^{2} = \frac{9}{4}$.$x^{2}+3x+\frac{9}{4}-5-\frac{9}{4}=0$$(x+\frac{3}{2})^{2} - \frac{20+9}{4} = 0$$(x+\frac{3}{2})^{2} - \frac{29}{4} = 0$$(x+\frac{3}{2})^{2} = (\frac{\sqrt{29}}{2})^{2}$Taking the square root on both sides:$x+\frac{3}{2} = \pm \frac{\sqrt{29}}{2}$$x = -\frac{3}{2} \pm \frac{\sqrt{29}}{2}$$x = \frac{-3 \pm \sqrt{29}}{2}$Thus,the solutions are $\frac{-3-\sqrt{29}}{2}$ and $\frac{-3+\sqrt{29}}{2}$.

Solve the following equation using the method of 'completing the square': $x^{2}+3x-5=0$.

Similar Questions

Which of the following is a quadratic equation in one variable?

Solve the following equation using the method of factorization and write its solution set: $\frac{x}{1-x} + \frac{1-x}{x} = \frac{13}{6}$

Does $(x-1)^{2}+2(x+1)=0$ have a real root? Justify your answer.

Find the discriminant of the following quadratic equation: $5x^{2} - 4\sqrt{2}x - 1 = 0$.

Examine whether the following equation is quadratic or not: $3x^{2} + 5\sqrt{x} + 3 = 0$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module