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(B) Step $1$: Solve equation $I$:$679 x^{2} - 168 x^{2} = 3066$$511 x^{2} = 3066$$x^{2} = \frac{3066}{511} = 6$$x = \pm \sqrt{6} \approx \pm 2.45$Step

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if $x < y$

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(B) Step $1$: Solve equation $I$:$679 x^{2} - 168 x^{2} = 3066$$511 x^{2} = 3066$$x^{2} = \frac{3066}{511} = 6$$x = \pm \sqrt{6} \approx \pm 2.45$Step $2$: Solve equation $II$:$\sqrt{144} y^{3} - 9 y^{3} = 1536$$12 y^{3} - 9 y^{3} = 1536$$3 y^{3} = 1536$$y^{3} = \frac{1536}{3} = 512$$y = \sqrt[3]{512} = 8$Step $3$: Compare $x$ and $y$:Since $x = \pm 2.45$ and $y = 8$,it is clear that $x < y$.

Solve the given two equations and select the correct answer from the given options:
$I.$ $679 x^{2} - 168 x^{2} = 3066$
$II.$ $\sqrt{144} y^{3} - 9 y^{3} = 1536$

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Solve the given two equations and select the correct answer from the given options:$I.$ $679 x^{2} - 168 x^{2} = 3066$$II.$ $\sqrt{144} y^{3} - 9 y^{3} = 1536$