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(A) Given equations are:$7x + 3y = 26$  --- $(1)$$2x + 17y = -41$ --- $(2)$To eliminate $x$,multiply equation $(1)$ by $2$ and equation $(2)$ by $7$:$

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if $x > y$

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(A) Given equations are:$7x + 3y = 26$  --- $(1)$$2x + 17y = -41$ --- $(2)$To eliminate $x$,multiply equation $(1)$ by $2$ and equation $(2)$ by $7$:$(7x + 3y = 26) 	imes 2 \Rightarrow 14x + 6y = 52$ --- $(3)$$(2x + 17y = -41) 	imes 7 \Rightarrow 14x + 119y = -287$ --- $(4)$Subtract equation $(4)$ from equation $(3)$:$(14x + 6y) - (14x + 119y) = 52 - (-287)$$-113y = 339$$y = -3$Substitute $y = -3$ into equation $(1)$:$7x + 3(-3) = 26$$7x - 9 = 26$$7x = 35$$x = 5$Comparing the values,$x = 5$ and $y = -3$. Since $5 > -3$,we have $x > y$.

Solve the given two equations and select the correct option.
$I.$ $7x + 3y = 26$
$II.$ $2x + 17y = -41$

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Solve the given two equations and select the correct option.$I.$ $7x + 3y = 26$$II.$ $2x + 17y = -41$