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(B) Step $1$: Solve for $x$.$x = \sqrt{172}$. Since $13^2 = 169$ and $14^2 = 196$,the value of $x$ is approximately $13.11$.Step $2$: Solve the quadra

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if $x < y$

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(B) Step $1$: Solve for $x$.$x = \sqrt{172}$. Since $13^2 = 169$ and $14^2 = 196$,the value of $x$ is approximately $13.11$.Step $2$: Solve the quadratic equation for $y$.$y^{2} - 29y + 210 = 0$.We need two numbers that multiply to $210$ and add up to $29$. These numbers are $14$ and $15$ ($14 	imes 15 = 210$ and $14 + 15 = 29$).So,$(y - 14)(y - 15) = 0$.This gives $y = 14$ or $y = 15$.Step $3$: Compare $x$ and $y$.Since $x \approx 13.11$ and $y$ is either $14$ or $15$,it is clear that $x Therefore,the correct option is $B$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $x = \sqrt{172}$
$II.$ $y^{2} - 29y + 210 = 0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $x = \sqrt{172}$$II.$ $y^{2} - 29y + 210 = 0$