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(D) For equation $I$: $x^{2}+14x+49=0$This can be written as $(x+7)^{2}=0$.Therefore,$x = -7$.For equation $II$: $y^{2}+9y=0$Factoring out $y$,we get

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if $x = y$ or relationship between $x$ and $y$ cannot be established.

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(D) For equation $I$: $x^{2}+14x+49=0$This can be written as $(x+7)^{2}=0$.Therefore,$x = -7$.For equation $II$: $y^{2}+9y=0$Factoring out $y$,we get $y(y+9)=0$.Therefore,$y = 0$ or $y = -9$.Comparing the values:If $x = -7$ and $y = 0$,then $x If $x = -7$ and $y = -9$,then $x > y$.Since the relationship changes depending on the value of $y$,the relationship between $x$ and $y$ cannot be established.

Solve the given two equations and provide the correct answer from the given options.
$I.$ $x^{2}+14x+49=0$
$II.$ $y^{2}+9y=0$

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Solve the given two equations and provide the correct answer from the given options.$I.$ $x^{2}+14x+49=0$$II.$ $y^{2}+9y=0$