Solve the given two equations and select the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For equation $I$: $77 x^{2}+58 x+8=0$Splitting the middle term: $77 x^{2}+44 x+14 x+8=0$$11 x(7 x+4)+2(7 x+4)=0$$(11 x+2)(7 x+4)=0$So,$x = -\frac{

Vedclass · Accepted Answer

if $x \ge y$

Vedclass · Answer

(B) For equation $I$: $77 x^{2}+58 x+8=0$Splitting the middle term: $77 x^{2}+44 x+14 x+8=0$$11 x(7 x+4)+2(7 x+4)=0$$(11 x+2)(7 x+4)=0$So,$x = -\frac{2}{11}$ or $x = -\frac{4}{7}$.For equation $II$: $42 y^{2}+59 y+20=0$Splitting the middle term: $42 y^{2}+35 y+24 y+20=0$$7 y(6 y+5)+4(6 y+5)=0$$(7 y+4)(6 y+5)=0$So,$y = -\frac{4}{7}$ or $y = -\frac{5}{6}$.Comparing values:$x_1 = -0.1818$,$x_2 = -0.5714$$y_1 = -0.5714$,$y_2 = -0.8333$Since $x_1 > y_1$,$x_1 > y_2$,$x_2 = y_1$,and $x_2 > y_2$,we conclude that $x \ge y$.

Solve the given two equations and select the correct option.
$I.$ $77 x^{2}+58 x+8=0$
$II.$ $42 y^{2}+59 y+20=0$

Similar Questions

Solve the given two equations and select the correct answer from the given options.
$I.$ $36 x^{4}+369 x^{2}+900=0$
$II.$ $144 y^{4}+337 y^{2}+144=0$

Sum of all distinct integral values of $\alpha$ such that the equation $x^2 - \alpha x + \alpha + 1 = 0$ has integral roots,is equal to-

The number of solutions of the equation $\log_{\sqrt{3}}(x^3 - 1) = \log_{\sqrt{3}}(x - 1) + 2$ is:

If $x$ is a solution of the equation $\sqrt{2x + 1} - \sqrt{2x - 1} = 1$ where $x \ge \frac{1}{2}$,then $\sqrt{4x^2 - 1}$ is equal to:

If $\alpha$ and $\beta$ are two real numbers satisfying $\alpha^2 + \beta^2 = 5$ and $3(\alpha^5 + \beta^5) = 11(\alpha^3 + \beta^3)$,then the value of $\alpha \beta$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Solve the given two equations and select the correct option.$I.$ $77 x^{2}+58 x+8=0$$II.$ $42 y^{2}+59 y+20=0$