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(B) For equation $I$: $18 x^{2}+18 x+4=0$Divide by $2$: $9 x^{2}+9 x+2=0$$9 x^{2}+6 x+3 x+2=0$$3 x(3 x+2)+1(3 x+2)=0$$(3 x+1)(3 x+2)=0$$x = -\frac{1}{

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if $x \geq y$

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(B) For equation $I$: $18 x^{2}+18 x+4=0$Divide by $2$: $9 x^{2}+9 x+2=0$$9 x^{2}+6 x+3 x+2=0$$3 x(3 x+2)+1(3 x+2)=0$$(3 x+1)(3 x+2)=0$$x = -\frac{1}{3}, -\frac{2}{3}$For equation $II$: $12 y^{2}+29 y+14=0$$12 y^{2}+21 y+8 y+14=0$$3 y(4 y+7)+2(4 y+7)=0$$(3 y+2)(4 y+7)=0$$y = -\frac{2}{3}, -\frac{7}{4}$Comparing values:$x_1 = -0.33, x_2 = -0.66$$y_1 = -0.66, y_2 = -1.75$Since $x_1 > y_1$,$x_1 > y_2$,$x_2 = y_1$,and $x_2 > y_2$,we conclude $x \geq y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $18 x^{2}+18 x+4=0$
$II.$ $12 y^{2}+29 y+14=0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $18 x^{2}+18 x+4=0$$II.$ $12 y^{2}+29 y+14=0$