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(C) Step $1$: Solve equation $I$.$x^{3} 	imes 13 = x^{2} 	imes 247$Dividing both sides by $x^{2}$ (assuming $x 
eq 0$):$x = \frac{247}{13} = 19$Ste

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$x < y$

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(C) Step $1$: Solve equation $I$.$x^{3} 	imes 13 = x^{2} 	imes 247$Dividing both sides by $x^{2}$ (assuming $x 
eq 0$):$x = \frac{247}{13} = 19$Step $2$: Solve equation $II$.$y^{1 / 3} 	imes 14 = 294 \div y^{2 / 3}$Multiply both sides by $y^{2 / 3}$:$y^{1 / 3} 	imes y^{2 / 3} 	imes 14 = 294$$y^{(1/3 + 2/3)} 	imes 14 = 294$$y^{1} 	imes 14 = 294$$y = \frac{294}{14} = 21$Step $3$: Compare $x$ and $y$.Since $x = 19$ and $y = 21$,it is clear that $x < y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{3} \times 13 = x^{2} \times 247$
$II.$ $y^{1 / 3} \times 14 = 294 \div y^{2 / 3}$

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Solve the given two equations and select the correct answer from the given options.$I.$ $x^{3} \times 13 = x^{2} \times 247$$II.$ $y^{1 / 3} \times 14 = 294 \div y^{2 / 3}$