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(B) For equation $I$: $16x^2 + 20x + 6 = 0$Dividing by $2$: $8x^2 + 10x + 3 = 0$$8x^2 + 6x + 4x + 3 = 0$$2x(4x + 3) + 1(4x + 3) = 0$$(2x + 1)(4x + 3)

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$x > y$

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(B) For equation $I$: $16x^2 + 20x + 6 = 0$Dividing by $2$: $8x^2 + 10x + 3 = 0$$8x^2 + 6x + 4x + 3 = 0$$2x(4x + 3) + 1(4x + 3) = 0$$(2x + 1)(4x + 3) = 0$$x = -1/2$ or $x = -3/4$For equation $II$: $10y^2 + 38y + 24 = 0$Dividing by $2$: $5y^2 + 19y + 12 = 0$$5y^2 + 15y + 4y + 12 = 0$$5y(y + 3) + 4(y + 3) = 0$$(5y + 4)(y + 3) = 0$$y = -4/5$ or $y = -3$Comparing values:$x_1 = -0.5$,$x_2 = -0.75$$y_1 = -0.8$,$y_2 = -3$Since $-0.5 > -0.8$,$-0.5 > -3$,$-0.75 > -0.8$,and $-0.75 > -3$,we conclude that $x > y$.

Solve the given two equations and choose the correct answer from the given options.
$I.$ $16x^2 + 20x + 6 = 0$
$II.$ $10y^2 + 38y + 24 = 0$

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Solve the given two equations and choose the correct answer from the given options.$I.$ $16x^2 + 20x + 6 = 0$$II.$ $10y^2 + 38y + 24 = 0$