Speed of an electron in Bohr's 7^{text{th}} o | vedclass

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(D) According to Bohr's model,the speed of an electron in the $n^{	ext{th}}$ orbit is given by $V_n \propto \frac{Z}{n}$.For a Hydrogen atom,the atom

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$8.4$

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(D) According to Bohr's model,the speed of an electron in the $n^{	ext{th}}$ orbit is given by $V_n \propto \frac{Z}{n}$.For a Hydrogen atom,the atomic number $Z = 1$,so $V_n \propto \frac{1}{n}$.Therefore,the ratio of speeds in the $3^{	ext{rd}}$ and $7^{	ext{th}}$ orbits is $\frac{V_3}{V_7} = \frac{7}{3}$.Substituting the given value $V_7 = 3.6 	imes 10^6\,m/s$:$V_3 = \frac{7}{3} 	imes 3.6 	imes 10^6\,m/s$.$V_3 = 7 	imes 1.2 	imes 10^6\,m/s = 8.4 	imes 10^6\,m/s$.

Speed of an electron in Bohr's $7^{\text{th}}$ orbit for Hydrogen atom is $3.6 \times 10^6\,m/s$. The corresponding speed of the electron in $3^{\text{rd}}$ orbit,in $m/s$ is $........\times 10^6$.

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