Standing waves are produced in a 10 ; m long | vedclass

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(C) The length of the string is $l = 10 \; m$. The number of segments is $p = 5$. The wave velocity is $v = 20 \; m/s$.For a string vibrating in $p$ s

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$5$

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(C) The length of the string is $l = 10 \; m$. The number of segments is $p = 5$. The wave velocity is $v = 20 \; m/s$.For a string vibrating in $p$ segments,the length $l$ is related to the wavelength $\lambda$ by the formula $l = p \cdot \frac{\lambda}{2}$.Substituting the values,we get $10 = 5 \cdot \frac{\lambda}{2}$,which simplifies to $\lambda = \frac{10 \cdot 2}{5} = 4 \; m$.The frequency $f$ is given by the relation $f = \frac{v}{\lambda}$.Substituting the values,$f = \frac{20 \; m/s}{4 \; m} = 5 \; Hz$.

Standing waves are produced in a $10 \; m$ long stretched string. If the string vibrates in $5$ segments and the wave velocity is $20 \; m/s$,the frequency is ... $Hz$.

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