Starting from radium,the radioactive disintegration process terminates when the following is obtained:

The end product of the $(4n + 1)$ radioactive disintegration series is:

During the emission of a positron from a nucleus, the mass number of the daughter element remains the same but the atomic number

${}_{90}Th^{232} \rightarrow {}_{82}Pb^{208}$. The number of $\alpha$ and $\beta$-particles emitted during the above reaction is:

The atomic mass of an element is $12.00710 \, amu$. If there are $6$ neutrons in the nucleus of the atom of the element,the binding energy per nucleon of the nucleus will be $....... \, MeV$.
($e^{-} = 0.00055 \, amu$,$p = 1.00814 \, amu$,$n = 1.00893 \, amu$)

In the following nuclear reaction,the other product is
$_{52}Te^{130} + _{1}H^{2} \xrightarrow{\quad} _{53}I^{131} + ?$