State the separation technique you would apply for the separation of the following:
$(a)$ Sodium chloride from its solution in water
$(b)$ Tea leaves from tea
$(c)$ Iron pins from sand
$(d)$ Different pigments from an extract of leaves
$(e)$ Butter from curd
$(f)$ Fine mud particles suspended in water.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Evaporation: Sodium chloride is a non-volatile solute,so it can be recovered from its aqueous solution by evaporating the water.
$(b)$ Filtration: Tea leaves are insoluble solids that can be separated from the liquid tea using a filter or sieve.
$(c)$ Magnetic separation: Iron pins are magnetic,while sand is not; therefore,a magnet can be used to attract and separate the pins.
$(d)$ Chromatography: This technique is used to separate different pigments based on their differential solubility in a solvent.
$(e)$ Centrifugation: Butter particles are lighter than the liquid in curd; spinning the mixture at high speed forces the denser components outward,separating the butter.
$(f)$ Decantation and filtration: Fine mud particles can be allowed to settle (sedimentation) followed by decantation,or removed directly using filtration.

Explore More

Similar Questions

The teacher instructed three students $A$,$B$ and $C$ respectively to prepare a $50\%$ (mass by volume) solution of sodium hydroxide $(NaOH)$. $A$ dissolved $50\,g$ of $NaOH$ in $100\,mL$ of water,$B$ dissolved $50\,g$ of $NaOH$ in $100\,g$ of water while $C$ dissolved $50\,g$ of $NaOH$ in water to make $100\,mL$ of solution. Which one of them has made the desired solution and why?

Which of the following are homogeneous in nature?
$(i)$ ice $(ii)$ wood $(iii)$ soil $(iv)$ air

Calculate the mass of sodium sulphate required to prepare its $20\%$ (mass percent) solution in $100\,g$ of water. (in $,g$)

Difficult
View Solution

Why is blood a mixture and graphite an element? Mention any one reason for each.

$(a)$ $7\, g$ of iron filings and $4\, g$ of sulphur powder is treated with dilute sulphuric acid at room temperature. Name the gas produced.
$(b)$ The same mixture is heated strongly,cooled and then treated with dilute sulphuric acid. Which gas would be produced?
$(c)$ What is the cause of this difference in results of chemical reaction in different conditions?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo