State True or False for the following statements:
$(i)$ Only carbocation is formed by homolytic cleavage of a bond.
$(ii)$ By heterolytic cleavage of a bond,a carbocation or carbanion is formed.
$(iii)$ The carbon of a carbanion is $sp^2$ and the carbon of a carbocation is $sp^3$.
$(iv)$ The carbon of a carbanion is $sp^3$ and the carbon of a carbocation is $sp^2$.

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(D) $(i)$ False: Homolytic cleavage results in the formation of free radicals,not carbocations.
$(ii)$ True: Heterolytic cleavage results in the unequal distribution of electrons,leading to the formation of a carbocation $(C^+)$ or a carbanion $(C^-)$.
$(iii)$ False: The carbon of a carbanion is $sp^3$ hybridized (pyramidal geometry),and the carbon of a carbocation is $sp^2$ hybridized (planar geometry).
$(iv)$ True: As explained in $(iii)$,the carbanion carbon is $sp^3$ and the carbocation carbon is $sp^2$.
Final Answer: $(i-F, ii-T, iii-F, iv-T)$

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