State which pairs of triangles in the figure are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(NONE) In $\triangle LMP$ and $\triangle DEF$:
$\frac{LM}{DE} = \frac{2.7}{4} = 0.675$
$\frac{LP}{DF} = \frac{3}{6} = 0.5$
$\frac{MP}{EF} = \frac{2}{5} = 0.4$
Since the ratios of the corresponding sides are not equal (i.e.,$\frac{LM}{DE} \neq \frac{LP}{DF} \neq \frac{MP}{EF}$),the two triangles are not similar.

Explore More

Similar Questions

In the figure,$AD$ is a median of a triangle $ABC$ and $AM \perp BC$. Prove that:
$AB^{2} = AD^{2} - BC \cdot DM + \left(\frac{BC}{2}\right)^{2}$

In the figure,$ABD$ is a triangle right-angled at $A$ and $AC \perp BD$. Show that $AB^2 = BC \cdot BD$.

Difficult
View Solution

An aeroplane leaves an airport and flies due north at a speed of $1000\, km/h$. At the same time,another aeroplane leaves the same airport and flies due west at a speed of $1200\, km/h$. How far apart will be the two planes after $1 \frac{1}{2}$ hours?

Difficult
View Solution

$E$ is a point on the side $AD$ produced of a parallelogram $ABCD$ and $BE$ intersects $CD$ at $F.$ Show that $\Delta ABE \sim \Delta CFB$.

In the figure,$D$ is a point on side $BC$ of $\Delta ABC$ such that $\frac{BD}{CD} = \frac{AB}{AC}$. Prove that $AD$ is the bisector of $\angle BAC$.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo