Statement-1 : Secondary & Tertiary alcohols c | vedclass

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(C) Statement-$1$ is correct: Lucas reagent $(conc. \ HCl + ZnCl_2)$ reacts with tertiary alcohols immediately to form turbidity,while secondary alcoh

Vedclass · Accepted Answer

Statement-$1$ is correct and Statement-$2$ is incorrect.

Vedclass · Answer

(C) Statement-$1$ is correct: Lucas reagent $(conc. \ HCl + ZnCl_2)$ reacts with tertiary alcohols immediately to form turbidity,while secondary alcohols take about $5-10$ minutes to form turbidity. Thus,they can be distinguished. Statement-$2$ is incorrect: Dichromate test (oxidation with $K_2Cr_2O_7/H^+$) is used to distinguish primary,secondary,and tertiary alcohols based on the products formed (aldehyde/acid,ketone,and no reaction/alkene respectively). However,it is not a specific test to distinguish between secondary and tertiary alcohols alone as effectively as the Lucas test or Victor Meyer's test,and specifically,both secondary and tertiary alcohols do not show the same color change pattern as primary alcohols. Therefore,Statement-$2$ is considered incorrect in the context of specific distinction.

Column-$I$ (Reagents)	Column-$II$ (Products)
$A$. $HCl + ZnCl_2$	$i$. $CH_3CH=CHCH_3$
$B$. $HBr$	$ii$. $CH_3CH_2CH_2CH_2Cl$
$C$. $SOCl_2$	$iii$. $CH_3CH_2CH_2CH_2Br$
$D$. $H_2SO_4, \Delta$	$iv$. $CH_3CH_2CH_2CH_2Cl$

Statement-$1$ : Secondary $\&$ Tertiary alcohols can be distinguished by Lucas reagent.
Statement-$2$ : Secondary $\&$ Tertiary alcohols can be distinguished by dichromate test.

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Statement-$1$ : Secondary $\&$ Tertiary alcohols can be distinguished by Lucas reagent. Statement-$2$ : Secondary $\&$ Tertiary alcohols can be distinguished by dichromate test.