Statement-I: Benzene gives Friedel-Crafts rea | vedclass

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(B) Statement-$I$ is correct because benzene undergoes Friedel-Crafts alkylation and acylation in the presence of a Lewis acid catalyst like $AlCl_3$.

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Statement-$I$ is correct but Statement-$II$ is incorrect.

Vedclass · Answer

(B) Statement-$I$ is correct because benzene undergoes Friedel-Crafts alkylation and acylation in the presence of a Lewis acid catalyst like $AlCl_3$.Statement-$II$ is incorrect because substituted benzenes with strongly electron-withdrawing groups (e.g.,$-NO_2$,$-SO_3H$,$-CN$,$-COR$) deactivate the ring significantly,making them unreactive towards Friedel-Crafts reactions. Additionally,amino groups ($-NH_2$,$-NHR$,$-NR_2$) form complexes with the Lewis acid catalyst,which also inhibits the reaction.

Statement-$I$: Benzene gives Friedel-Crafts reaction.
Statement-$II$: All substituted benzenes give Friedel-Crafts reaction.
Choose the correct statement:

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Statement-$I$: Benzene gives Friedel-Crafts reaction.Statement-$II$: All substituted benzenes give Friedel-Crafts reaction.Choose the correct statement: