Stationary waves of frequency 300, Hz are for | vedclass

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(A) The velocity of the wave is given by $v = n\lambda$,where $n$ is the frequency and $\lambda$ is the wavelength.Given $v = 1200\, m/s$ and $n = 300

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(A) The velocity of the wave is given by $v = n\lambda$,where $n$ is the frequency and $\lambda$ is the wavelength.Given $v = 1200\, m/s$ and $n = 300\, Hz$.Calculating the wavelength: $\lambda = \frac{v}{n} = \frac{1200}{300} = 4\, m$.The distance between a node and the adjacent antinode in a stationary wave is always $\frac{\lambda}{4}$.Therefore,the required distance $= \frac{4\, m}{4} = 1\, m$.

Stationary waves of frequency $300\, Hz$ are formed in a medium in which the velocity of sound is $1200\, m/s$. The distance between a node and the neighbouring antinode is ... $m$.

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