The strongest reducing agent among the follow | vedclass

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Question

(D) The reducing power of halide ions depends on their ability to lose electrons,which is inversely proportional to their electronegativity and direct

Vedclass · Accepted Answer

$I^{-}$

Vedclass · Answer

(D) The reducing power of halide ions depends on their ability to lose electrons,which is inversely proportional to their electronegativity and directly proportional to their ionic size.As we move down the group from $F^{-}$ to $I^{-}$,the ionic size increases,making it easier to lose an electron.Therefore,the reducing strength order is $F^{-} Thus,$I^{-}$ is the strongest reducing agent among the given options.

The strongest reducing agent among the following is:

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