Sulphur on boiling with NaOH solution gives | vedclass

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Question

(B) When sulphur is boiled with an aqueous solution of sodium hydroxide $(NaOH)$,it undergoes a disproportionation reaction to form sodium thiosulphat

Vedclass · Accepted Answer

$Na_2S_2O_3 + Na_2S$

Vedclass · Answer

(B) When sulphur is boiled with an aqueous solution of sodium hydroxide $(NaOH)$,it undergoes a disproportionation reaction to form sodium thiosulphate $(Na_2S_2O_3)$ and sodium sulphide $(Na_2S)$.The balanced chemical equation is:$3S + 6NaOH \xrightarrow{\Delta} 2Na_2S + Na_2S_2O_3 + 3H_2O$Alternatively,it is often represented as:$4S + 6NaOH \rightarrow 2Na_2S + Na_2S_2O_3 + 3H_2O$Given the options,the correct products are $Na_2S_2O_3$ and $Na_2S$.

Sulphur on boiling with $NaOH$ solution gives

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