Sum of the two binary numbers (100010)_2 and | vedclass

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(A) First,convert the binary numbers to decimal:$(100010)_2 = (1 	imes 2^5) + (0 	imes 2^4) + (0 	imes 2^3) + (0 	imes 2^2) + (1 	imes 2^1) + (0

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$(111101)_2$

Vedclass · Answer

(A) First,convert the binary numbers to decimal:$(100010)_2 = (1 	imes 2^5) + (0 	imes 2^4) + (0 	imes 2^3) + (0 	imes 2^2) + (1 	imes 2^1) + (0 	imes 2^0) = 32 + 0 + 0 + 0 + 2 + 0 = (34)_{10}$$(11011)_2 = (1 	imes 2^4) + (1 	imes 2^3) + (0 	imes 2^2) + (1 	imes 2^1) + (1 	imes 2^0) = 16 + 8 + 0 + 2 + 1 = (27)_{10}$Sum in decimal: $(34)_{10} + (27)_{10} = (61)_{10}$Now,convert $(61)_{10}$ back to binary:$61 \div 2 = 30$Remainder $1$ $(LSD)$$30 \div 2 = 15$Remainder $0$$15 \div 2 = 7$Remainder $1$$7 \div 2 = 3$Remainder $1$$3 \div 2 = 1$Remainder $1$$1 \div 2 = 0$Remainder $1$ $(MSD)$Reading remainders from bottom to top,we get $(111101)_2$.

Sum of the two binary numbers $(100010)_2$ and $(11011)_2$ is

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