Sumit lends ₹ 10000 for 2 years at 20 % per a | vedclass

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(C) The principal amount $P = ₹ 10000$,rate $R = 20 \%$ per annum,and time $T = 1$ $year$.The total amount after $1$ $year$ is calculated as:$A_1 = P

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$7200$

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(C) The principal amount $P = ₹ 10000$,rate $R = 20 \%$ per annum,and time $T = 1$ $year$.The total amount after $1$ $year$ is calculated as:$A_1 = P \left(1 + \frac{R 	imes T}{100}ight) = 10000 \left(1 + \frac{20 	imes 1}{100}ight) = 10000 	imes 1.2 = ₹ 12000$.Sumit receives ₹ $6000$ after $1$ $year$. The remaining principal amount for the second year is:$P_{new} = 12000 - 6000 = ₹ 6000$.Now,the amount to be received at the end of the second year on the remaining principal is:$A_2 = P_{new} \left(1 + \frac{R 	imes T}{100}ight) = 6000 \left(1 + \frac{20 	imes 1}{100}ight) = 6000 	imes 1.2 = ₹ 7200$.

Sumit lends ₹ $10000$ for $2$ $years$ at $20 \%$ per annum simple interest. After $1$ $year,$ he receives ₹ $6000$. How much (in ₹) will he receive next year?

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