Suppose two elements X and Y combine to form | vedclass

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(C) For $XY_{2}$:$0.05 \ mol = 5 \ g$$1 \ mol = \frac{5}{0.05} = 100 \ g/mol$So,$X + 2Y = 100$ --- $(i)$For $X_{2}Y_{3}$:$3.011 	imes 10^{23}$ molecu

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$40, 30$

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(C) For $XY_{2}$:$0.05 \ mol = 5 \ g$$1 \ mol = \frac{5}{0.05} = 100 \ g/mol$So,$X + 2Y = 100$ --- $(i)$For $X_{2}Y_{3}$:$3.011 	imes 10^{23}$ molecules is $0.5 \ mol$ (since $1 \ mol = 6.022 	imes 10^{23}$ molecules).$0.5 \ mol = 85 \ g$$1 \ mol = 85 	imes 2 = 170 \ g/mol$So,$2X + 3Y = 170$ --- $(ii)$Multiply equation $(i)$ by $2$:$2X + 4Y = 200$ --- $(iii)$Subtract $(ii)$ from $(iii)$:$(2X + 4Y) - (2X + 3Y) = 200 - 170$$Y = 30$Substitute $Y = 30$ into $(i)$:$X + 2(30) = 100$$X + 60 = 100$$X = 40$Therefore,the atomic masses of $X$ and $Y$ are $40$ and $30$ respectively.

Suppose two elements $X$ and $Y$ combine to form two compounds $XY_{2}$ and $X_{2}Y_{3}$. If $0.05 \ mol$ of $XY_{2}$ weighs $5 \ g$ while $3.011 \times 10^{23}$ molecules of $X_{2}Y_{3}$ weighs $85 \ g$,then atomic masses of $X$ and $Y$ are respectively :

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