The IUPAC name of the complex [CrCl_2(H_2O)_4 | vedclass

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Question

(B) To name the complex $[CrCl_2(H_2O)_4]NO_3$,we follow $IUPAC$ nomenclature rules:$1$. Ligands are named in alphabetical order: $aqua$ $(H_2O)$ come

Vedclass · Accepted Answer

Tetraaquadichlorochromium $(III)$ nitrate

Vedclass · Answer

(B) To name the complex $[CrCl_2(H_2O)_4]NO_3$,we follow $IUPAC$ nomenclature rules:$1$. Ligands are named in alphabetical order: $aqua$ $(H_2O)$ comes before $chloro$ $(Cl^-)$.$2$. There are $4$ water molecules,so we use the prefix $tetra-$,and $2$ chloride ions,so we use the prefix $di-$.$3$. The metal is $chromium$. To find its oxidation state $(x)$: $x + 2(-1) + 4(0) = +1$ (since $NO_3$ is $-1$),so $x = +3$.$4$. The oxidation state is written as $(III)$ in parentheses.$5$. The anion $NO_3^-$ is named as $nitrate$ at the end.Thus,the correct name is $tetraaquadichlorochromium(III)$ nitrate.

The $IUPAC$ name of the complex $[CrCl_2(H_2O)_4]NO_3$ is

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