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(B) $1$. In the given cyclic compound,the double bond is present between $C1$ and $C2$. According to $IUPAC$ rules,the double bond should be given pri

Vedclass · Accepted Answer

$6-$Bromo$-1-$methylcyclohexene

Vedclass · Answer

(B) $1$. In the given cyclic compound,the double bond is present between $C1$ and $C2$. According to $IUPAC$ rules,the double bond should be given priority and numbered such that it gets the lowest possible locants ($1$ and $2$).$2$. We start numbering from the carbon atom of the double bond that allows the substituent to have the lowest possible number.$3$. If we number the double bond carbons as $1$ and $2$,the methyl group is at position $1$ and the bromine atom is at position $6$.$4$. Thus,the correct numbering gives the $6-$bromo and $1-$methyl substituents.$5$. Combining these,the name is $6-$Bromo$-1-$methylcyclohexene.

The $IUPAC$ name of the given compound is:

Similar Questions

The $IUPAC$ name(s) of the following compound is(are):
$[A]$ $4-$methylchlorobenzene
$[B]$ $4-$chlorotoluene
$[C]$ $1-$chloro$-4-$methylbenzene
$[D]$ $1-$methyl$-4-$chlorobenzene

Identify the bond line formula of Neopentane.

$IUPAC$ name of $CH_3-CH(CH_3)-CH_2-CH=CH_2$ is

The correct nomenclature for the following compound is:

In the given compound,the number of $2^{\circ}$ carbon atom/s is. . . . . .
$CH_3-C(CH_3)(H)-CH(H)-C(CH_3)(H)-CH_3$

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