The IUPAC name of OHC-CH_2-CH=CH-CHO is | vedclass

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(D) The structure is $OHC-CH_2-CH=CH-CHO$. The longest carbon chain containing both aldehyde groups has $5$ carbon atoms. Numbering starts from the en

Vedclass · Accepted Answer

Pent-$2$-ene-$1,5$-dial

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(D) The structure is $OHC-CH_2-CH=CH-CHO$. The longest carbon chain containing both aldehyde groups has $5$ carbon atoms. Numbering starts from the end that gives the double bond the lowest possible locant. Numbering from left to right: $C_1(CHO)-C_2(H_2)-C_3(H)=C_4(H)-C_5(CHO)$. The double bond is at $C_3$. Numbering from right to left: $C_1(CHO)-C_2(H)=C_3(H)-C_4(H_2)-C_5(CHO)$. The double bond is at $C_2$. Since $2 Thus,the $IUPAC$ name is $Pent-2-ene-1,5-dial$.

The $IUPAC$ name of $OHC-CH_2-CH=CH-CHO$ is

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Write $IUPAC$ names of the following compounds:
$(i)$ $(CH_3)_2CH-CH=CH-CH_2-CH=C(CH_3)-CH(C_2H_5)-CH_3$
$(ii)$ The structure is shown below:
$(iii)$ $CH_2=C(CH_2CH_2CH_3)_2$
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