The IUPAC name of the following compound (E)- | vedclass

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(A) $1.$ The longest carbon chain containing both multiple bonds has $7$ carbon atoms,so the parent name is hept. $2.$ Numbering the chain from left t

Vedclass · Accepted Answer

$(E)-2-	ext{hepten}-4-	ext{yne}$

Vedclass · Answer

(A) $1.$ The longest carbon chain containing both multiple bonds has $7$ carbon atoms,so the parent name is hept. $2.$ Numbering the chain from left to right gives the multiple bonds the lowest locants ($2$ and $4$). The double bond is at $C2$ and the triple bond is at $C4$. $3.$ Since the higher priority groups ($CH_3$ and the alkyne group) are on opposite sides of the double bond,the configuration is $(E)$. $4.$ Therefore,the $IUPAC$ name is $(E)-2-	ext{hepten}-4-	ext{yne}$.

The $IUPAC$ name of the following compound $(E)-CH_3-CH=CH-C \equiv C-CH_2-CH_3$ is

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