The INCORRECT match in the following is | vedclass

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(B) The relationship between standard Gibbs free energy change $(\Delta G^o)$ and the equilibrium constant $(K)$ is given by the equation: $\Delta G^o

Vedclass · Accepted Answer

$\Delta G^o < 0, K < 1$

Vedclass · Answer

(B) The relationship between standard Gibbs free energy change $(\Delta G^o)$ and the equilibrium constant $(K)$ is given by the equation: $\Delta G^o = -RT \ln K$ or $\Delta G^o = -2.303 \, RT \log K$. $1$. If $\Delta G^o 0$,which implies $K > 1$ (Spontaneous reaction). $2$. If $\Delta G^o = 0$,then $\ln K = 0$,which implies $K = 1$ (Equilibrium). $3$. If $\Delta G^o > 0$,then $\ln K Therefore,the match $\Delta G^o < 0, K < 1$ is $INCORRECT$.

The $INCORRECT$ match in the following is

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