The pH of 10^{-8} M aqueous solution of HCl | vedclass

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(C) For a very dilute solution of a strong acid,the contribution of $H^+$ ions from the auto-ionization of water cannot be ignored.Total $[H^+] = [H^+

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$6 < pH < 7$ (Between $6$ and $7$)

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(C) For a very dilute solution of a strong acid,the contribution of $H^+$ ions from the auto-ionization of water cannot be ignored.Total $[H^+] = [H^+]_{HCl} + [H^+]_{H_2O} = 10^{-8} + 10^{-7} = 10^{-8} + 10 	imes 10^{-8} = 11 	imes 10^{-8} \ M$.$pH = -\log[H^+] = -\log(11 	imes 10^{-8}) = 8 - \log(11) \approx 8 - 1.04 = 6.96$.Since the solution is acidic,the $pH$ must be slightly less than $7$. Thus,$6 < pH < 7$.

The $pH$ of $10^{-8} \ M$ aqueous solution of $HCl$ is

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