The pH of a 10^{-10} M HCl solution is appro | vedclass

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(B) For a very dilute acid solution like $10^{-10} \ M$ $HCl$,the concentration of $H^+$ ions from the auto-ionization of water $(10^{-7} \ M)$ cannot

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(B) For a very dilute acid solution like $10^{-10} \ M$ $HCl$,the concentration of $H^+$ ions from the auto-ionization of water $(10^{-7} \ M)$ cannot be ignored.Total $[H^+] = [H^+]_{HCl} + [H^+]_{H_2O} = 10^{-10} + 10^{-7} \ M$.Total $[H^+] = 10^{-7} \ (1 + 10^{-3}) \approx 10^{-7} \ M$.$pH = -\log[H^+] = -\log(10^{-7}) = 7$.Since the solution is acidic,the $pH$ will be slightly less than $7$,but for practical purposes,it is approximately $7$.

The $pH$ of a $10^{-10} \ M$ $HCl$ solution is approximately

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