The pH of D_2O and H_2O at 298 K is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) At $298 \ K$,the ionic product of water $(K_w)$ is $1.0 	imes 10^{-14}$,so $pH = -\log[H^+] = 7.0$. For heavy water $(D_2O)$,the dissociation con

Vedclass · Accepted Answer

$7.35, 7.0$

Vedclass · Answer

(B) At $298 \ K$,the ionic product of water $(K_w)$ is $1.0 	imes 10^{-14}$,so $pH = -\log[H^+] = 7.0$. For heavy water $(D_2O)$,the dissociation constant $(K_w')$ is approximately $1.6 	imes 10^{-15}$ at $298 \ K$. Since $pD = -\log[D^+]$,and $[D^+] = \sqrt{K_w'} = \sqrt{1.6 	imes 10^{-15}} \approx 4.0 	imes 10^{-8} \ M$. Therefore,$pD = -\log(4.0 	imes 10^{-8}) \approx 7.4$. Thus,the $pH$ (or $pD$) of $D_2O$ is approximately $7.35$ and for $H_2O$ it is $7.0$.

The $pH$ of $D_2O$ and $H_2O$ at $298 \ K$ is

Similar Questions

The ionic product of water increases with which of the following changes?

The $pH$ of the solution is $4$. The hydrogen ion concentration of the solution in $mol/L$ is

The $pH$ of a soft drink is $3.82$. Its hydrogen ion concentration will be

Observe the following solutions:
$I$. Black coffee
$II$. $0.2 \ M \ NaOH$
$III$. Lemon juice
$IV$. Lime water
$V$. Human Saliva
$VI$. Tomato juice
The number of solutions with $pH$ less than $7$ is

When $KBr$ is dissolved in water,$K^{+}$ ions are

Vedclass Test Series

Exam Paper Generator

Online Exam Module