The IUPAC name of the compound CHO-(CH_2)_4-C | vedclass

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Question

(A) The given compound is $CHO-(CH_2)_4-COOH$.In $IUPAC$ nomenclature,the carboxylic acid group $(-COOH)$ is given priority over the aldehyde group $(

Vedclass · Accepted Answer

$6$-oxohexanoic acid

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(A) The given compound is $CHO-(CH_2)_4-COOH$.In $IUPAC$ nomenclature,the carboxylic acid group $(-COOH)$ is given priority over the aldehyde group $(-CHO)$.The carbon of the carboxylic acid group is assigned position $1$.Counting the carbon chain,we have $6$ carbons in total.The aldehyde group at position $6$ is treated as a substituent and is named as '$oxo$' or '$formyl$'.According to $IUPAC$ rules,when the carbon of the aldehyde group is not part of the principal chain,it is named as '$6$-oxohexanoic acid' or '$6$-formylhexanoic acid'. However,'$6$-oxohexanoic acid' is the standard $IUPAC$ name.

The $IUPAC$ name of the compound $CHO-(CH_2)_4-COOH$ is:

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The $IUPAC$ name of $CH_3-CO-CO-CH_3$ is

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