The IUPAC names of CH_3-CH(OH)-CH_2-C(CH_3)(O | vedclass

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(B) The correct option is $B$.For the first structure $CH_3-CH(OH)-CH_2-C(CH_3)(OH)-CH_3$:The longest carbon chain containing the principal functional

Vedclass · Accepted Answer

$2$-methyl-$2, 4$-pentanediol and $3$-cyano-$1, 5$-pentanedinitrile

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(B) The correct option is $B$.For the first structure $CH_3-CH(OH)-CH_2-C(CH_3)(OH)-CH_3$:The longest carbon chain containing the principal functional groups $(-OH)$ has $5$ carbons.Numbering is done to give the lowest locants to the $-OH$ groups,which are at positions $2$ and $4$ from either side.Next,we apply the lowest locant rule for the substituent (methyl group). Numbering from right to left gives the methyl group position $2$,while left to right gives position $4$.Thus,the correct $IUPAC$ name is $2$-methyl-$2,4$-pentanediol.For the second structure $CH_2(CN)-CH(CN)-CH_2(CN)$:According to $IUPAC$ rules,the longest carbon chain containing the principal functional groups $(-CN)$ is selected.Here,the chain is $5$ carbons long (pentane),with nitrile groups at positions $1$ and $5$.The third $-CN$ group is treated as a substituent at position $3$,named as a cyano group.Thus,the $IUPAC$ name is $3$-cyano-$1,5$-pentanedinitrile.

The $IUPAC$ names of $CH_3-CH(OH)-CH_2-C(CH_3)(OH)-CH_3$ and $CH_2(CN)-CH(CN)-CH_2(CN)$ are:

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Write the $IUPAC$ names of the following structures:
$(i)$ $CH_3-CH=CH-CH(Br)-CH_3$
$(ii)$ $CH_2=C(CH_3)-CH(Br)-CH_3$
$(iii)$ $CH_3-CH=C(CH_3)-CH(Br)-CH_3$
$(iv)$ $CH_3-C(CH_3)=CH-CH_2Br$
$(v)$ $CH_3-CH=CH-CH_2Br$
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