The LCM of two prime numbers x and y (x y | vedclass

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(A) Given that the $LCM$ of two prime numbers $x$ and $y$ is $161$.Since $x$ and $y$ are prime numbers,their $HCF$ is $1$.We know that for any two num

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$-2$

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(A) Given that the $LCM$ of two prime numbers $x$ and $y$ is $161$.Since $x$ and $y$ are prime numbers,their $HCF$ is $1$.We know that for any two numbers,$LCM 	imes HCF = 	ext{Product of the numbers}$.Therefore,$x 	imes y = 161$.By prime factorization of $161$,we get $161 = 7 	imes 23$.Since $x > y$,we assign $x = 23$ and $y = 7$.Now,calculating the value of $3y - x$:$3(7) - 23 = 21 - 23 = -2$.

The $LCM$ of two prime numbers $x$ and $y$ $(x > y)$ is $161$. The value of $3y - x$ is

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