The ldots ldots ldots ldotsth term of the A.P | vedclass

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(C) Given the $A.P.$ is $8, 11, 14, 17, \ldots$Here,the first term $a = 8$.The common difference $d = 11 - 8 = 3$.Let the $n^{th}$ term $T_n = 272$.Th

Vedclass · Accepted Answer

$89$

Vedclass · Answer

(C) Given the $A.P.$ is $8, 11, 14, 17, \ldots$Here,the first term $a = 8$.The common difference $d = 11 - 8 = 3$.Let the $n^{th}$ term $T_n = 272$.The formula for the $n^{th}$ term of an $A.P.$ is $T_n = a + (n - 1)d$.Substituting the values,we get:$272 = 8 + (n - 1)3$$272 - 8 = (n - 1)3$$264 = (n - 1)3$$n - 1 = 264 / 3$$n - 1 = 88$$n = 89$.Thus,the $89^{th}$ term of the $A.P.$ is $272$.

The $\ldots \ldots \ldots \ldots$th term of the $A.P.$ $8, 11, 14, 17, \ldots$ is $272$.

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