The rms speeds of the molecules of Hydrogen,O | vedclass

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(A) The formula for the $rms$ speed of gas molecules is $V_{RMS} = \sqrt{\frac{3RT}{M_{W}}}$,where $R$ is the universal gas constant,$T$ is the absolu

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$V_{H} > V_{O} > V_{C}$

Vedclass · Answer

(A) The formula for the $rms$ speed of gas molecules is $V_{RMS} = \sqrt{\frac{3RT}{M_{W}}}$,where $R$ is the universal gas constant,$T$ is the absolute temperature,and $M_{W}$ is the molar mass of the gas.Since the temperature $T$ is the same for all gases,we have $V_{RMS} \propto \frac{1}{\sqrt{M_{W}}}$.The molar masses are: $M_{H} = 2 \ g/mol$,$M_{O} = 32 \ g/mol$,and $M_{C} = 44 \ g/mol$.Since $M_{H}  \frac{1}{\sqrt{M_{O}}} > \frac{1}{\sqrt{M_{C}}}$.Therefore,$V_{H} > V_{O} > V_{C}$.

The $rms$ speeds of the molecules of Hydrogen,Oxygen,and Carbon dioxide at the same temperature are $V_{H}$,$V_{O}$,and $V_{C}$ respectively. Then:

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