The $pH$ of $0.1 \, M$ aqueous solutions of $NaCl$,$CH_3COONa$ and $NH_4Cl$ will follow the order:
- A$NaCl < CH_3COONa < NH_4Cl$
- B$NH_4Cl < NaCl < CH_3COONa$
- C$NH_4Cl < CH_3COONa < NaCl$
- D$NaCl < NH_4Cl < CH_3COONa$
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Which of the following will not undergo hydrolysis in water?
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When a salt of a weak acid and a weak base is dissolved in water at $25\,^{\circ}C$,the $pH$ of the resulting solution will always :-
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View SolutionAssertion $(A)$: The aqueous solution of $CH_3COONa$ is alkaline in nature.
Reason $(R)$: Acetate ion undergoes anionic hydrolysis.
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Reason $(R)$: Acetate ion undergoes anionic hydrolysis.
The correct answer is
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