The IUPAC name (including the stereochemical | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. Identify the principal functional group: The ketone group $(-C=O)$ has higher priority than the alkene and the bromo substituent. Thus, the c

Vedclass · Accepted Answer

$(S)-5$-bromo-$(Z)$-hex-3-en-2-one

Vedclass · Answer

(A) $1$. Identify the principal functional group: The ketone group $(-C=O)$ has higher priority than the alkene and the bromo substituent. Thus, the chain is numbered starting from the end closer to the ketone, making it a $hex-3-en-2-one$ derivative. The ketone carbon is $C-2$, the alkene carbons are $C-3$ and $C-4$, and the chiral carbon with the bromine is $C-5$.$2$. Determine the stereochemistry of the alkene: The two hydrogen atoms are on the same side of the double bond, which corresponds to the $(Z)$ configuration.$3$. Determine the configuration of the chiral center at $C-5$: The groups attached to $C-5$ are $-Br$ (priority $1$), $-CH=CH-COCH_3$ (priority $2$), $-CH_3$ (priority $3$), and $-H$ (priority $4$). With the hydrogen atom pointing away (dashed bond), the sequence $1 \rightarrow 2 \rightarrow 3$ is counter-clockwise, which corresponds to the $(S)$ configuration.$4$. Combine the parts: The name is $(S)-5$-bromo-$(Z)$-hex-3-en-2-one.

The $IUPAC$ name (including the stereochemical notation for the chiral carbon) of the given structure is:

Similar Questions

The $IUPAC$ name of $CH_3-CO-CH(C_2H_5)-CH(CH_3)_2$ is

The correct $IUPAC$ name of the given structure is:

The $IUPAC$ name of $CH_3-CH(OH)-CH_2-CH(CH_3)-CHO$ will be

Name the compounds whose line formulae are given below.

The $IUPAC$ name of the given compound is: $(CH_3)_3C-CH=CH-C_6H_4Br-p$

Vedclass Test Series

Exam Paper Generator

Online Exam Module