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(B) The slope $m$ of the line passing through $(x_1, y_1) = \left(-\frac{1}{2}, 1\right)$ and $(x_2, y_2) = (1, 3)$ is given by:$m = \frac{y_2 - y_1}{

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$-5/4$

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(B) The slope $m$ of the line passing through $(x_1, y_1) = \left(-\frac{1}{2}, 1\right)$ and $(x_2, y_2) = (1, 3)$ is given by:$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 1}{1 - (-1/2)} = \frac{2}{3/2} = \frac{4}{3}$Using the point-slope form $y - y_1 = m(x - x_1)$ with point $(1, 3)$:$y - 3 = \frac{4}{3}(x - 1)$$3y - 9 = 4x - 4$$4x - 3y + 5 = 0$To find the $x$-intercept,set $y = 0$:$4x - 3(0) + 5 = 0$$4x = -5$$x = -\frac{5}{4}$Thus,the $x$-intercept is $-\frac{5}{4}$.

The $x$-intercept of a line passing through the points $\left(-\frac{1}{2}, 1\right)$ and $B(1, 3)$ is

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