The I-V graph for a conductor at two differen | vedclass

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Question

(A) From the $I-V$ graph,the slope represents $1/R$. For temperature $t_1 = 100^{\circ} C$,the angle is $45^{\circ}$,so $1/R_1 = 	an 45^{\circ} = 1$,

Vedclass · Accepted Answer

$3 	imes 10^{-5}$

Vedclass · Answer

(A) From the $I-V$ graph,the slope represents $1/R$. For temperature $t_1 = 100^{\circ} C$,the angle is $45^{\circ}$,so $1/R_1 = 	an 45^{\circ} = 1$,which gives $R_1 = 1 \Omega$. For temperature $t_2 = 400^{\circ} C$,the angle is $30^{\circ}$,so $1/R_2 = 	an 30^{\circ} = 1/\sqrt{3}$,which gives $R_2 = \sqrt{3} \Omega \approx 1.732 \Omega$. The temperature coefficient of resistance $\alpha$ is given by the formula: $\alpha = \frac{R_2 - R_1}{R_1 t_2 - R_2 t_1} = \frac{\sqrt{3} - 1}{1 	imes 400 - \sqrt{3} 	imes 100} = \frac{0.732}{400 - 173.2} = \frac{0.732}{226.8} \approx 3.22 	imes 10^{-3} /^{\circ} C$. Rounding to the nearest given option,the value is approximately $3 	imes 10^{-3} /^{\circ} C$.

The $I-V$ graph for a conductor at two different temperatures $100^{\circ} C$ and $400^{\circ} C$ is as shown in the figure. The temperature coefficient of resistance of the conductor is about (in per degree Celsius).

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