The IUPAC name of the compound shown in the i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. Identify the principal functional group: The $-COOH$ group is the principal functional group,so the parent chain is named as a pentanoic acid

Vedclass · Accepted Answer

$4-$hydroxy$-2-$methylpentanoic acid

Vedclass · Answer

(A) $1$. Identify the principal functional group: The $-COOH$ group is the principal functional group,so the parent chain is named as a pentanoic acid.$2$. Number the chain: Start numbering from the carbon of the $-COOH$ group as $C-1$. The chain is numbered to give the lowest possible locants to the substituents.$3$. Identify substituents: There is a methyl group at $C-2$ and a hydroxy group at $C-4$.$4$. Alphabetical order: 'Hydroxy' comes before 'methyl'.$5$. Final name: Combining these,the $IUPAC$ name is $4-$hydroxy$-2-$methylpentanoic acid.

The $IUPAC$ name of the compound shown in the image is:

Similar Questions

The correct $IUPAC$ name of the given structure is:

What is the $IUPAC$ name of the compound $CH_3-CH(CH_3)-CH_2-CH_2-Cl$?

The functional group present in sulphonic acid is:

What is the $IUPAC$ name of the following compound?
$HOOC-CH_2-CH(COOH)-CH_2-CH_2-COOH$

Rank the following groups in order of $R, S$ priority (Cahn-Ingold-Prelog priority rules,where $1$ is highest priority):
$A) -CH(CH_3)_2$
$B) -CH_2CH_2Br$
$C) -CH_2Br$
$D) -C(CH_3)_3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module