The IUPAC name for the following compound is | vedclass

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Question

(D) The carbonyl group (ketone) has higher priority than the double bond and the bromine substituent. Therefore,the numbering must start from the end

Vedclass · Accepted Answer

$7-$bromohept$-4-$en$-2-$one

Vedclass · Answer

(D) The carbonyl group (ketone) has higher priority than the double bond and the bromine substituent. Therefore,the numbering must start from the end closest to the carbonyl group.The structure is $Br(7)CH_2-CH_2(6)-CH(5)=CH(4)-CH_2(3)-CO(2)-CH_3(1)$.The parent chain has $7$ carbons,so the root is 'hept'.There is a double bond at position $4$ and a ketone at position $2$.The bromine substituent is at position $7$.Combining these,the $IUPAC$ name is $7-$bromohept$-4-$en$-2-$one.Thus,the correct option is $D$.

The $IUPAC$ name for the following compound is $BrCH_2-CH_2-CH=CH-CH_2-CO-CH_3$.

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