The pH of a solution of H_2O_2 is 6.0. Some c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $H_2O_2$ acts as a reducing agent towards strong oxidizing agents like $Cl_2$. The chemical reaction is: $H_2O_2 + Cl_2 \longrightarrow 2HCl + O_2

Vedclass · Accepted Answer

The $pH$ of resultant solution becomes less than $6.0$ and oxygen gas is liberated

Vedclass · Answer

(C) $H_2O_2$ acts as a reducing agent towards strong oxidizing agents like $Cl_2$. The chemical reaction is: $H_2O_2 + Cl_2 \longrightarrow 2HCl + O_2$. In this reaction,$HCl$ is produced,which is a strong acid. The formation of $HCl$ increases the concentration of $H^+$ ions in the solution. Consequently,the $pH$ of the resultant solution decreases (becomes less than $6.0$) and oxygen gas $(O_2)$ is evolved.

The $pH$ of a solution of $H_2O_2$ is $6.0$. Some chlorine gas is bubbled into this solution. Which of the following is correct?

Similar Questions

Calculate the molarity and $\% \ W/V$ of $40$ volume of $H_2O_2$ solution.

$H_2O_2$ reacts as a reducing agent with:
$(I)$ $KMnO_4$
$(II)$ $K_2Cr_2O_7$
$(III)$ $Ag_2O$
$(IV)$ $HNO_3$

Complete the following equations :
$(i) PbS_{(s)} + 4H_2O_{2_{(aq)}} \to$
$(ii) CO_{(g)} + 2H_{2_{(g)}} \xrightarrow{\text{cobalt catalyst}}$

In the gas phase,the $H-O-O-H$ dihedral angle in $H_{2}O_{2}$ is: (in $^{\circ}$)

By which of the following methods,$H_2O_2$ cannot be synthesized?

Vedclass Test Series

Exam Paper Generator

Online Exam Module