The pH of an aqueous solution of CH_3COONa of | vedclass

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Question

(D) $CH_3COONa$ is a salt of a weak acid $(CH_3COOH)$ and a strong base $(NaOH)$.For the hydrolysis of a salt of a weak acid and a strong base, the $p

Vedclass · Accepted Answer

$\frac{1}{2} pK_w + \frac{1}{2} pK_a + \frac{1}{2} \log C$

Vedclass · Answer

(D) $CH_3COONa$ is a salt of a weak acid $(CH_3COOH)$ and a strong base $(NaOH)$.For the hydrolysis of a salt of a weak acid and a strong base, the $pH$ is calculated using the formula:$pH = \frac{1}{2} (pK_w + pK_a + \log C)$Expanding this, we get:$pH = \frac{1}{2} pK_w + \frac{1}{2} pK_a + \frac{1}{2} \log C$Therefore, the correct option is $D$.

The $pH$ of an aqueous solution of $CH_3COONa$ of concentration $C \ M$ is given by:

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