The SI unit of magnetic permeability is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic field $B$ produced by a current element is given by the Biot-Savart Law:$B = \frac{\mu_0}{4\pi} \frac{I dl \sin(	heta)}{r^2}$Rearran

Vedclass · Accepted Answer

$Wb\;m^{-1}\;A^{-1}$

Vedclass · Answer

(C) The magnetic field $B$ produced by a current element is given by the Biot-Savart Law:$B = \frac{\mu_0}{4\pi} \frac{I dl \sin(	heta)}{r^2}$Rearranging for the permeability $\mu_0$:$\mu_0 = \frac{B \cdot r^2}{I \cdot dl \cdot \sin(	heta)}$Substituting the $SI$ units:$B$ is in $Wb/m^2$ (Tesla),$r$ is in $m$,$I$ is in $A$,$dl$ is in $m$.Therefore,the unit of $\mu_0$ is:$	ext{Unit} = \frac{(Wb/m^2) \cdot m^2}{A \cdot m} = \frac{Wb}{A \cdot m} = Wb\;m^{-1}\;A^{-1}$

The $SI$ unit of magnetic permeability is

Similar Questions

$A$ horizontal overhead power line carries a current of $90 \;A$ in east to west direction. What is the magnitude and direction of the magnetic field due to the current $1.5 \;m$ below the line?

The magnetic field at the origin due to a current element $i d l$ placed at a point with vector position $r$ is

Identify the correct statement.

$A$ wire in the form of a circular loop of one turn carrying a current produces a magnetic field $B$ at the centre. If the same wire is looped into a coil of two turns and carries the same current,the new value of magnetic induction at the centre is

$A$ charge $q$ moving in a circle of radius $r$ metre makes $n$ revolutions per second. The magnetic field at the centre of the circle is

Vedclass Test Series

Exam Paper Generator

Online Exam Module