The chi - 1/T graph for an alloy of paramagne | vedclass

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(A) According to Curie's law for paramagnetic materials,the magnetic susceptibility $\chi$ is given by $\chi = C 	imes (1/T)$,where $C$ is the Curie

Vedclass · Accepted Answer

$57$

Vedclass · Answer

(A) According to Curie's law for paramagnetic materials,the magnetic susceptibility $\chi$ is given by $\chi = C 	imes (1/T)$,where $C$ is the Curie constant.From the given graph,the slope of the line represents the Curie constant $C$.Slope $C = \frac{\Delta \chi}{\Delta (1/T)} = \frac{0.4}{7 	imes 10^{-3} 	ext{ K}^{-1}}$.$C = \frac{0.4}{0.007} = \frac{400}{7} \approx 57.14 	ext{ K}$.Rounding to the nearest integer,the Curie constant is $57 	ext{ K}$.

The $\chi - 1/T$ graph for an alloy of paramagnetic nature is shown in the figure. The Curie constant is,then....$K$.

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